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A sample of hydrogen gas occupies a volume of 6.38 L at 48.0°C and 0.490 atm. If it is desired to increase the volume of the gas sample to 8.10 L, while increasing its pressure to 0.655 atm, the temperature of the gas sample at the new volume and pressure must be ________°C.

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Answer:

The final temperature 271.77 °C

Step-by-step explanation:

Given:

Initial pressure
P_(1) =0.490 atm

Final pressure
P_(2) = 0.655 atm

Initial temperature
T_(1) = 48° C = 321 K

Initial volume
V_(1) = 6.38 L

Final volume
V_(2) = 8.10 L

From ideal gas equation,


(P_(1) V_(1) )/(T_(1) ) = (P_(2) V_(2) )/(T_(2) )


T_(2) = (P_(2) V_(2) )/(P_(1) V_(1) ) * T_(1)


T_(2) = (0.655 * 8.10 )/(0.490 * 6.38 ) * 321


T_(2) = 544.77 K


T_(2) = 271.77°C

Therefore, the final temperature 271.77 °C

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