Answer:
Frequency of the Rh-positive allele

Step-by-step explanation:
Given-
A represents the dominant gene i.e Rh-positive
a represents the recessive gene i.e Rh-negative
It is given that 84% of a population is Rh-positive. This means that 84% of a population will have genotype either Aa or AA
Now as per Hardy Weinberg's equation -
is the frequency of Aa or AA genotype
is the frequency of aa genotype
Frequency of recessive allele

As per first equation of HW equilibrium -

Substituting the value of q in above equation , we get
