Answer:
A. 0.972085
B. 0.028717
Explanation:
To solve this question, we proceed as follows;
First, we calculate the probability p = 2791.5/100000 = 0.027915
a) probability that a randomly chosen American women between the ages of 20 and 24 does not have a Chlamydia infection = 1-0.027915 = 0.972085
b) odds of a Chlamydia infection in the 20 to 24 year old US female population = number of people with thedisease to the number of people without it in a particular population
= 0.027915 / 0.972085 = 0.028717