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One trait in the peas that Mendel studied was seed color: some seeds were yellow and some seeds were green. A cross between a homozygous yellow line (GG) and a homozygous green line (gg) will result in F1 plants that are heterozygous (Gg) for this trait and produce yellow seeds. Cross between homozygous yellow and green pea plants When an F1 plant undergoes meiosis, what gamete types will it produce, and in what proportions? Use your understanding of Mendel’s Law of Segregation to label each gamete possibility as "correct" or "incorrect." View Available Hint(s)

User Dooburt
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Answer:

Gamete with alleles G and g in equal proportion i.e. 1/2 G: 1/2 g will be produced by the heterozygous pea plant.

Step-by-step explanation:

Mendel discovered the principles that governs inheritance in his several experiments. One of these principles is tha LAW OF SEGREGATION which states that the alleles of a gene will separate into gametes during meiosis (gamete formation) in equal proportion. In essence, each gamete will contain only one type of allele.

In this case, the gene responsible for seed colour possess two contrasting forms (alleles). The yellow allele (G) is dominant over the green allele (g) because the yellow allele masks the expression of the green allele in a heterozygous state (Gg). Thus, when this heterozygous yellow pea (Gg) undergoes meiosis, each allele will separate into gametes in a way that each gamete will contain one type of allele i.e. either G or g in equal proportion. If four gametes are produced, two if them will contain G allele (1/2G) while the other two will contain g allele (1/2g).