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A metal rod of length (L) moves with velocity (v), perpendicular to its length, in a magnetic field B, which is perpendicular to both the rod and its velocity. If the length of the rod is doubled, what happens to the electric field in the rod

User Jamespick
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1 Answer

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Step-by-step explanation:

If a metal rod of length L moves with velocity v is moving perpendicular to its length, in a magnetic field B, the induced emf is given by :


\epsilon=Blv

The electric field in the conductor is given by :


E=(\epsilon)/(l)\\\\E=(Blv)/(l)\\\\E=Bv

It is clear that the electric field is independent of the length of the rod. If the length of the rod is doubled, the electric field in the rod remains the same.

User Jason Lowenthal
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