Answer:
Step-by-step explanation:
work done by the beetle during the launch = F × d cosθ where θ is equal to 0°
change potential energy of the beetle = mgh = work done by the beetle
mgh = F d cosθ where h, height = 0.32 m and d = 0.796 mm
5.88 × 10-6 kg × 9.8 m/s² × 0.320 m / ( 0.796 ÷ 1000) m = F
F = 0.0232 N
b) the acceleration of the beetle in terms of g =
F = ma
mgh / d = ma
cancel m on both side
gh /d = a
0.320 g / ( 0.796 ÷ 1000) m = 402 .01 g