192k views
1 vote
A transverse traveling wave on a cord is represented by, where D and x are in meters and t is in seconds.

(a) Determine the wavelength.
(b) Determine the frequency.
(c) Determine the velocity (magnitude and direction). (
d) Determine the amplitude.
(e) Determine the maximum and minimum speeds of particles of the cord.

User Oksayt
by
4.5k points

1 Answer

0 votes

Answer with Explanation:

We are given that a transverse travelling wave on a cord is represented by


D=0.51sin(6.1x+76t)

Where D and x in meters

t(in seconds)

a.General equation of transverse wave


y=Asin(kx+\omega t)

By comparing we get

A=0.51


k=6.1


k=(2\pi)/(\lambda)

Wavelength,
\lambda=(2\pi)/(k)=(2\pi)/(6.1)=1.03

b.
\omega=76

Frequency,
f=(\omega)/(2\pi)=(76)/(2\pi)=12.096Hz

c.Velocity,
v=f\lambda=12.096* 1.03=12.46m/s

Direction:Towards negative x- axis

d.Amplitude,A=0.51 m

e.Maximum speed,
v_(max)=A\omega=0.51* 76=38.76 m/s

Minimum speed,
v_(min)=0

User GrayR
by
5.2k points