Answer with Explanation:
We are given that
Angle of incidence,
![i=30^(\circ)](https://img.qammunity.org/2021/formulas/physics/college/f80h6yswgb09zrj9qndu4meep9jeczsyrt.png)
Angle of refraction,
![r=19.24^(\circ)](https://img.qammunity.org/2021/formulas/physics/college/x4xzzb08wwpyuhnjz1hh9tl516mdsc8keo.png)
a.Refractive index of air,
![n_1=1](https://img.qammunity.org/2021/formulas/chemistry/high-school/jwkj62kaq9i0rg4lmp9y4t531xu0bkybqa.png)
We know that
![n_2sinr=n_1sini](https://img.qammunity.org/2021/formulas/physics/college/dmpr1ljd3wzo7bgxmz0j4f7sv7gjsey4q3.png)
![n_2=(n_1sin i)/(sin r)=(sin30)/(sin19.24)=1.517](https://img.qammunity.org/2021/formulas/physics/college/oyts88t55dlgvehzv5vkbsgsz9xiph12gj.png)
b.Wavelength of red light in vacuum,
![\lambda=632.8nm=632.8* 10^(-9) m](https://img.qammunity.org/2021/formulas/physics/college/9lf9sh02zc892rmtk2tcnv73djbkfa8ghg.png)
![1nm=10^(-9) m](https://img.qammunity.org/2021/formulas/physics/college/sw2mjzehctri2dadwpghnn8yskdxbb9k13.png)
Wavelength in the solution,
![\lambda'=(\lambda)/(n_2)](https://img.qammunity.org/2021/formulas/physics/college/menj4hcawaelcp43chlgd85ujuljpyyghl.png)
![\lambda'=(632.8)/(1.517)=417nm](https://img.qammunity.org/2021/formulas/physics/college/rfsc32mwfeq6utgvq5cg2esnrzvbvei8me.png)
c.Frequency does not change .It remains same in vacuum and solution.
Frequency,
![\\u=(c)/(\lamda)=(3* 10^8)/(632.8* 10^(-9))](https://img.qammunity.org/2021/formulas/physics/college/e0n8vzkpnew9ec96bs8cavxc86hpk0wxnn.png)
Where
![c=3* 10^8 m/s](https://img.qammunity.org/2021/formulas/physics/college/puhgvmohp8t4dkq6ppf0dzqn0wlku24g8e.png)
Frequency,
![\\u=4.74* 10^(14)Hz](https://img.qammunity.org/2021/formulas/physics/college/wfc9wcdei1uxvwrs7ugaz1kdql8ca20l9b.png)
d.Speed in the solution,
![v=(c)/(n_2)](https://img.qammunity.org/2021/formulas/physics/college/3rnxucgmyfzxz00sfrrefa0i04k8di7l8i.png)
![v=(3* 10^8)/(1.517)=1.98* 10^8m/s](https://img.qammunity.org/2021/formulas/physics/college/s2tdo9fs3g65yhp1bvomj9r3087j51qshj.png)