Question

n a system for separating gases a tank containing a mixture of hydrogen and carbon dioxide is connected to a much larger tank where the pressure is kept very low. The two tanks are separated by a porous membrane through which the molecules must effuse. If the initial partial pressures of each gas is 5.00 atm, what will be the mole fraction of hydrogen in the tank after the partial pressure of carbon dioxide has declined to 4.50 atm

Answer 1

The mol fraction of the hydrogen gas = 0.526

Step-by-step explanation:

Step 1: data given

mixture of hydrogen and carbon dioxide

the initial partial pressures of each gas is 5.00 atm

the partial pressure of carbon dioxide has declined to 4.50 atm

Step 2: Calculate total pressure

Total pressure = 4.5 atm + 5.0 atm

Total pressure = 9.5 atm

Step 3: Calculate mol fraction

Partial pressure = mole fraction * total pressure

Mol fraction = partial pressure / total pressure

Mol fraction carbon dioxide = 4.5 atm / 9.5 atm

Mol fraction carbon dioxide = 0.474

Mol fraction of hydrogen = 1 - 0.474 = 0.526

The mol fraction of the hydrogen gas = 0.526