Question

A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How would the student properly label this solution? A. 2.00 M NaCl B. 116.9 g/ L NaCl C. 116.9 M NaCl D. 2.00 M/L NaCl

Answer 1

Answer: The molarity of the solution is 2.00 M

Step-by-step explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in L = 1.00 L

moles of solute =
`\frac{\text {given mass}}{\text {molar mass}}=(116.9g)/(58.5g/mol)=2.00moles`

`Molarity=(2.00mol)/(1.00L)=2.00M`

Thus the molarity of the solution is 2.00 M