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How many grams of solute are needed to make 5.00 L of 3.00M glucose (molar mass = 180 g/mole)?

1 Answer

4 votes

Answer:

2700g glucose

Step-by-step explanation:

If we want 3 mol/L in 5L we must have 15 moles of glucose because 3 x 5 = 15.

The molar mass of glucose is given as 180 g/mol

to cancel moles from the equation we multiply the molar mass by the number of moles. 180 x 15 = 2700.

2700g glucose

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