Question

Magnesium metal burns in the presence of oxygen gas to produce solid magnesium oxide. You are given 4.00 grams of magnesium and an excess of oxygen gas in a tank. How many grams of magnesium oxide can be produced?

Answer 1

We can produce 6.63 grams of Magnesium oxide

Step-by-step explanation:

Step 1: Data given

Mass of magnesium = 4.00 grams

Molar mass of Magnesium = 24.305 g/mol

O2 is in excess

Molar mass of Magnesium oxide = 40.3044 g/mol

Step 2: The balanced equation

2Mg + O2 → 2MgO

For 2 moles Magnesium we need 1 mol oxygen gas to produce 2 moles magnesiumoxide

Step 3: Calculate moles magnesium

Moles Mg = 4.00 grams / 24.305 g/mol

Moles Mg = 0.1646 moles

Step 4: Calculate moles Magnesiumoxide

For 2 moles Magnesium we need 1 mol oxygen gas to produce 2 moles magnesiumoxide

For 0.1646 moles Mg we'll have 0.1646 moles MgO

Step 5: Calculate mass magnesium oxide

Mass MgO = Moles MgO * molar mass MgO

Mass MgO = 0.1646 moles* 40.3044 g/mol

Mass MgO = 6.63 grams

We can produce 6.63 grams of Magnesium oxide

Answer 2

6.63g of MgO

Step-by-step explanation:

Magnesium (Mg) reacts with oxygen (O) in

Equation of reaction

Mg + O₂ → MgO

From the stoichiometry of the reaction, 1 mole of Mg gives 1 mole of MgO

1 mole = molar mass

Molar mass of Mg = 24.3 g/mol

Molarmass of MgO = (24.3 + 16.0) = 40.3g/mol

24.3 g of Mg = 40.3g of MgO

4 g of Mg = x g of MgO

x = (4 * 40.3) / 24.3

x = 6.63 g of MgO