Question

Assume that endogenous acid production is 40 meq during a 12-hr period. A urine sample collected during this time contains 30 mmol NH4 and 15 meq titratable acid. If the body is in steady state for HCO3-, how much HCO3- must be in this urine sample?

Answer 1

Thus, the Quantity of
`HCo_(3)^(-)` Present in urine sample in 24 hours is 35mmol

Step-by-step explanation:

Acid Production in 12 hours = 40 meq

For, 24 hours = 40 meq × 2

Acid Production in 24 hours = 80 meq

Urine sample for
`NH4^(+)` = 30mmol

`HCo_(3)^(-)` Present in Urine Sample in 24 hours

= Acid Production - Urine sample for
`NH4^(+)` - Titratable Acid

= 80 - 30 - 15

= 50 - 15

= 35mmol

`HCo_(3)^(-)` Present in urine sample in 24 hours is 35mmol