Answer:
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)
Step-by-step explanation:
Given
Outer diameter of the wire = b ⇒ R = b/2
Diameter of the clindrical hole at the center = a ⇒ r = a/2
The current that flows from left to right and is uniformly spread over the region between a and b = i
We apply Ampere's Law
Using the following formula for a/2 ≤ x ≤ b/2
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)