Answer:
45% probability that exactly two children inherited the X-linked genetic disorder.
Explanation:
X assumes values 0,1,2,3,4
P(0) = 0.04
P(1) = 0.26
P(2) = 0.45
P(3) = 0.2
P(4) = 0.05
This is our probability distribution
The probability distribution that we have in this problem means that:
4% probability that no children inherited the X-linked genetic disorder.
26% probability that exactly one children inherited the X-linked genetic disorder
45% probability that exactly two children inherited the X-linked genetic disorder.
20% probability that exactly three children inherited the X-linked genetic disorder
5% probability that all four children inherited the X-linked genetic disorder
What is the probability that exactly two children inherited the X-linked genetic disorder?
45%