Question

Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 320 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor

Answer 1

The crate's coefficient of kinetic friction on the floor is 0.23.

Step-by-step explanation:

Given that,

Mass of the crate, m = 300 kg

One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 320 N using a rope connected to the crate.

The crate slides with a constant speed. It means that the net force acting on it is 0. Net force acting on it is given by :

`F_1+F_2=\mu N\\\\\mu=(F_1+F_2)/(mg)\\\\\mu=(390+320)/(300* 10)\\\\\mu=0.23`

So, the crate's coefficient of kinetic friction on the floor is 0.23.