Question

What is the temperature, in kelvin, of 4.15 moles of a gas at a pressure of 7.30 atmospheres in a 21.7 liter container?

P
V
=
n
R
T


R = 0.0821
a
t
m
⋅
L
m
o
l
⋅
K

Answer 1

461.91 Kelvin

Step-by-step explanation:

P = 7.30 atm

V = 21.7 liters

n = 4.15 moles

R = 0.0821 atm

T = ?

PV = nRT

(7.30) (21.7) = (4.15) (0.0821) (T)

158.41 = 0.34 (T)

T = 465.91 Kelvin