Question

A white card has an 8 on one side and an unknown number on the other side.A red card has a 4 on one side with a different unknown number on the other side. Of the two cards are flipped, the four possible total scores are 12, 13, 14,15.Find two possible pairs of values, (W1, R1); (W2, R2), for the unknown numbers.

Answer 1

Answer: The correct possible values for (W1,R1); (W2,R2) are (10,5); (9,6)

Step-by-step explanation: A card has two sides and when flipped only one side is revealed.

Having two cards (white and red) with four possible total score said of 12, 13, 14, 15, the number on the white card will be 8 and 9 while those on the red card will be 4 and 6 or 8 and 10 on the white and 4 and 5 on the red.

Arriving at the missing numbers is logical. To solve it, you have to find two numbers to add to the existing number of the white card ‘8’ and red card ‘4’ at a time to give the possible totals.

Therefore; combination 1 = 8 + 4 = 12

Combination 2= 8 + 6 or 10 + 4= 14

Combination 3= 9 + 4 or 8 + 5 = 13

Combination 4= 9 + 6 or 10 + 5= 15

Answer 2

(10,5) and (9,6)

Explanation:

•White card has 8 on one side and an unknown value on the other side. Let's take unknown value as p, i.e

Outcome of white card = (8, p)

•Red card has 4 on one side and unknown an the other side. Let's take q as the unknown figure on red card. I.e

Outcome of red card (4, q)

When the two cards are flipped the possible sum of their values will be:

•12 (8+4);

•8+q;

•4+p; and

•p+q

We are given that their sum values are 12, 13, 14 and 15

Therefore, let's now assume the following:

• 8+q = 13, or 8+q=14,

•4+p = 14, or 4+p = 13

Solving, we now have:

R1) 8+q = 13 => q= 13-8 = 5

or

R2) 8+q = 14=> q=14-8 = 6

W1) 4+p = 14 => p=14-4 = 10

or

W2) 4+p =13 => p=13-4 = 9

From the calculations, we can deduce that the two possible pair of values for the unknown nubers are:

(10,5) and (9,6)