Answer:
5 units.
Explanation:
Use the following equation:
distance (d) = √((x₂ - x₁)² + (y₂ - y₁)²)
Let:
(x₁ , y₁) = (5 , -1)
(x₂ , y₂) = (9 , 2)
Plug in the corresponding numbers to the corresponding variables:
d = √((9 - 5)² + (2 - (-1))²)
d = √((4)² + (2 + 1)²)
d = √((16) + (3)²)
d = √(16 + 9)
d = √(25)
d = 5
Your distance between points (9 , 2) & (5, -1) is 5 units.
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