Question

An Atwood machine is constructed using two wheels (with the masses concentrated at the rims). The left wheel has a mass of 2.4 kg and radius 24.26 cm. The right wheel has a mass of 2 kg and radius 33.62 cm. The hanging mass on the left is 1.62 kg and on the right 1.09 kg. m3 m1 m4 m2 What is the acceleration of the system

Answer 1

The acceleration of the system is 0.7305 m/s²

Step-by-step explanation:

Given that:

m₁ = 2.4 kg , m₂ = 2 kg, m₃ = 1.62 kg, m₄ = 1.09 kg

Torque (τ) = mra

For left pulley:

T₁r₁ - T₂r₁ = m₁r₁a

Dividing through by r₁

T₁ - T₂ = m₁a .... 1)

For right pulley:

T₂r₂ - T₃r₂ = m₂r₂a

Dividing through by r₂

T₂ - T₃ = m₂a .... 2)

Also

m₃g - T₁ = m₃a ... 3)

T₃ - m₄g = m₄a ... 4)

adding equations 1, 2, 3 and 4 to get:

(m₁ + m₂ + m₃ + m₄)a = (m₃ - m₄)g

(2.4 + 2 + 1.62 + 1.09)a = (1.62 - 1.09)9.8

7.11a = 5.194

a = 5.194 / 7.11 = 0.7305

a = 0.7305 m/s²

The acceleration of the system is 0.7305 m/s²