Question

A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light.

B) Determine the power delivered to the same automobile light.

C) What potential difference is needed to produce a current of 5.0 mA through a 2.0 ? resistor?

Answer 1

The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

Step-by-step explanation:

Given:

(A)

Current
`I = 1` A

Voltage
`V = 12` V

For finding the resistance,

`V = IR`

`R = (V)/(I)`

`R = (12)/(1)`

`R =` 12Ω

(B)

For finding power delivered,

`P = I^(2) R`

`P = (1) ^(2) * 12`

`P = 12` Watt

(C)

For finding the potential difference,

`V = IR`

`V = 5 * 10^(-3) * 2`

`V = 10 * 10^(-3)`

`V = 0.01` V

Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V