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In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.50×1016 kg and a radius of 9.00 km .What is the speed of a satellite orbiting 4.60 km above the surface?

User Cesara
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Answer:

8.58 m/s.

Step-by-step explanation:

Given,

Mass of the asteroid,M = 1.50 x 10¹⁶ Kg

radius = 9 Km

distance of the satellite, r = 4.60 Km

Speed of the satellite = ?

R = 9 + 4.60 = 13.60 Km

Speed of the satellite rotating in orbit


v = \sqrt{(GM)/(R)}

G is gravitational constant


v = \sqrt{(6.67* 10^(-11)* 1.50* 10^(16))/(13.60* 10^3)}

v = 8.58 m/s

Speed of the satellite is equal to 8.58 m/s.

User Anthony C
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