Answer:
Explanation:
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = maximum oxygen uptake for elite athletes.
µ = mean maximum oxygen uptake for elite athletes
σ = standard deviation
From the information given,
µ = 80
σ = 5.8
1)
the probability that an elite athlete has a maximum oxygen uptake of at least 65 ml/kg is expressed as
P(x ≥ 65) = 1 - P(x < 65)
For x = 65
z = (65 - 80)/5.8 = - 2.59
Looking at the normal distribution table, the probability corresponding to the z score is 0.0048
P(x ≥ 65) = 1 - 0.0048 = 0.9952
2)
the probability that an elite athlete has a maximum oxygen uptake of 70 ml/kg or lower is expressed as
P(x ≤ 70)
For x = 70,
z = (70 - 80)/5.8 = - 1.72
Looking at the normal distribution table, the probability corresponding to the z score is 0.043
P(x ≤ 70) = 0.43
3)
For someone with a maximum oxygen uptake of 3030 ml/kg,
z = (30 - 80)/5.8 = - 8.62
Probability = 0.00015
The probability of an elite athlete having a maximum oxygen uptake of 30 ml/kg is very low. Thus the answer is NO