Question

Sunlight, with an intensity of 637 W / m 2 , strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is 8.33 m 2 . What is the force F in micronewtons that acts on the surface due to the sunlight?

Answer 1

Force of 17.6 micrometer is acting on the surface due to the sunlight.

Step-by-step explanation:

Given that,

Intensity of sunlight is
`I=637\ W/m^2`

It strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is
`A=8.33\ m^2`

`P=F* v`

So, force is given by :

`F=(IA)/(c)`

c is speed of light

`F=(637* 8.33)/(3* 10^8)\\\\F=17.6\ \mu N`

So, force of 17.6 micrometer is acting on the surface due to the sunlight.