Question

In peas, a gene controls flower color such that R = purple and r = white. In an isolated pea patch, there are 36 purple-flowering plants and 64 white-flowering plants. Assuming Hardy-Weinberg equilibrium, what is the value of q for this population?

a. 0.36.
b. 0.64 .
c. 0.75.
d. 0.80.

Answer 1

D

Step-by-step explanation:

R= Purple,

r= white

Let q for recessive allele and p for dominant allele

p+q=1

Frequency of q²= 64/100= 0.64

So the frequency of the recessive genotype is 0.64 , that is, the frequency of qq(q²) is 0.64.

So by Hardy-Weinberg equilibrium

Therefore, the frequency of the recessive allele, usually called q, is √0.64= 0.80