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Based on a​ poll, 6464​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is the probability that among threethree randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to​ respond? The probability that at least one of them is careful about personal information is nothing

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Answer:

Explanation:

We would assume a binomial distribution for the number of Internet users that are more careful about personal information when using a public​ Wi-Fi hotspot. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 64% = 64/100 = 0.64

q = 1 - p = 1 - 0.64

q = 0.36

n = 3

1) The probability that among three randomly selected internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot is expressed as

P(x ≥ 1) = 1 - P(x < 1)

P(x < 1) = P(x = 0)

P(x = 0) = 3C0 × 0.64^0 × 0.36^(3 - 0)

P(x = 0) = 0.047

P(x ≥ 1) = 1 - 0.047 = 0.953

If more information is provided, the result would be biased.

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