Question

Find the zeros of the function p(x) = -9x^2 + 1

Answer 1

Explanation:

zeroes = x intercept.

to find the x intercept we let y or in this case p(x) = 0

Hence,

-9x^2 + 1 = 0

-9x^2 = -1

x^2 = 1/9

x = 1/3

x = -1/3