Answer:
The force-moment system felt at O =


Step-by-step explanation:
The diagram shown below completes the other half of the question.As such, we will make sure to work in conjunction to that :
Given that;
the tension in the cable, T, in kN, is 10 plus the last digit of your SID,
T = (10 + 7)kN
T = 17 kN
Also; from the diagram ; Co-ordinates at points are
O (0,0,0)
A(6,12,9)
B(17,22,2)
However;
AB = OA - OB
AB = (6i + 12j + 19k) -(17i +22j + 2k)
AB = -11i -10j + 17 k

For the unit vector along AB is expressed as:

Component of Tension


From the diagram , at point O; the reactive species generated are opposite in nature.
Therefore;

Also, to determine the moment of T about point O ; we have:

![\\M \left[\begin{array}{ccc}1&j&k\\-6&-12&-19\\-8.28&-7.52&12.79\end{array}\right]](https://img.qammunity.org/2021/formulas/engineering/college/5uozo4w755yz99a7ax9w10xhwuc2sxu0b1.png)
![\\\\\\M = [ (-12*12.79)-(-19*7.52)i - (-6)(12.79)-(-19)(-8.28)j+(-6)(-7.52)-(-12)(-8.28)]](https://img.qammunity.org/2021/formulas/engineering/college/i4hexyccbrn2c326y2zhnwphp3flsiaw2k.png)

