Question

People end up tossing 12% of what they buy at the grocery store. Assume this is the true population proportion and that you plan to take a sample survey of 540 grocery shoppers to further investigate their behavior. Show the sampling distribution of p, the proportion of groceries thrown out by your sample respondents. If required, round your answer to four decimal places.

Answer 1

he sampling distribution of p is normal with mean p = 0.12

the standard deviation =
`\sqrt{(p(1-p))/(n) } =\sqrt{(0.12(1-0.12))/(540) }=0.014`

Explanation:

A sampling distribution is a probability distribution obtained from a larger number of samples gotten from a specific population. It shows all the possible result that can be gotten from each sample of a population

Given that:

p = 12% = 0.12

n = 540

the sampling distribution of p is normal with mean p = 0.12

the standard deviation =
`\sqrt{(p(1-p))/(n) } =\sqrt{(0.12(1-0.12))/(540) }=0.014`

It is shown in the graph attached