Question

Find the 76th term of the arithmetic sequence 16, 14, 12, ...
I need help pls

Answer 1

your answer is like this

Explanation:

a)16. d)-2

an=a+(n-1)d

a76=16+(76-1)-2

=16-150

=-136

Answer 2

Answer: The answer is -134

Step-by-step explanation: Common Difference:

d=a_2-a_1=(14)-(16)=-2d=a2​−a1​=(14)−(16)=−2

a_n=a_1+(n-1)dan​=a1​+(n−1)d

\text{76th term:}76th term:

a_{76}=16 + (76-1)(-2)a76​=16+(76−1)(−2)

a_{76}=16 + (75)(-2)a76​=16+(75)(−2)

a_{76}=-134a76​=−134