Question

Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation distance of 0.02 m. Determine the magnitude of the electrical force of repulsion between them

Answer 1

The electric force between them is 878.9 N

Step-by-step explanation:

Given:

Identical charge
`q = -6.25 * 10^(-6)`C

Separation between two charges
`r = 0.02` m

For finding the electrical force,

According to the coulomb's law

`F = (k q^(2) )/(r^(2) )`

Here, force between two balloons are repulsive because both charges are same.

Where
`k = 9 * 10^(9)`

`F = (9 * 10^(9) * (-6.25 * 10^(-6) )^(2) )/(4 * 10^(-4) )`

`F = 878.9` N

Therefore, the electric force between them is 878.9 N