Question

1) A balloon is filled with helium to a volume of 13.6 Lat a pressure of

101 kPa. If the pressure decreases to 35.0 kPa what is the new volume
of the balloon (assuming temperature is constant)? (Boyle's Law)

Answer 1

39.2

Step-by-step explanation:

using p1xv1=p2xv2

101x13.6= 1373.6

1373.6/35.0 =39.2457

round because of sigfig :)

Answer 2

Final volume = 835 L

Step-by-step explanation:

Given data:

Initial volume = 13.6 L

Initial pressure = 101 Kpa

Final pressure = 35.0 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 KPa × 13.6 L = 35 KPa × V₂

V₂ = 1373.6 KPa. L/35 KPa

V₂ = 835 L