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A block is hung by a string from the inside roof of a van. When the van goes straight ahead at a speed of , the block hangs vertically down. But when the van maintains this same speed around an unbanked curve , the block swings toward the outside of the curve. Then the string makes an angle with the vertical. Find .

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Answer:

θ = tan ( v²/gr)

Step-by-step explanation:

This exercise we must find the angle of the string, for this we use Newton's second law

F = m a

Let's create a reference system with one vertical axis and the other in radial direction,

vertical axis


T_(y) - W = 0

T_{y} = W

Radial axis

T_{r} = m a

As we are in a curve, they relate it to a switchboard

a = v² / r

We use trigonometry to find the components of the tension

cos θ = T_{y} / T

sin θ = T_{r} / T

T_{y} = T cos θ

T_{r} = T sin θ

we substitute

T cos θ = mg

T = m g / cos θ

T sin θ = m v² / r

(mg / cos θ) sin θ = m v² / r

tan θ = v² / g r

θ = tan ( v²/gr)

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