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Please help this is my last time asking these 2 questions I need the correct answers no more fake links pls

Please help this is my last time asking these 2 questions I need the correct answers-example-1
Please help this is my last time asking these 2 questions I need the correct answers-example-1
Please help this is my last time asking these 2 questions I need the correct answers-example-2
User Sweber
by
3.8k points

2 Answers

12 votes

Answer for 1st question:

The answer is A. 4/20

Explanation:

The probability of landing on a vowel would be 2/5.

The probability of landing on an even number would be 2/4.

Now we just need to solve the probability of landing on a vowel and an even number.

2/5 x 2/4 = 4/20.

Thereore, the probability of landing on a vowel and an even number is 4/20.

Answer for 2nd question:

The answer is B. 1/20

Explanation:

The probability of landing on a C would be 1/5.

The probability of landing on a 4 would be 1/4.

Again, we just need to solve the probability of landing on a C and a 4.

1/5 x 1/4 = 1/20.

Therefore, the probability of landing a C and a 4 is 1/20.

User Sbhatla
by
3.4k points
12 votes

Both of these scenarios are independent probability. We can use the given formula P(A and B) = P(A) * P(B). In other words, we will find the probability for each event and multiply them by each other.

To find the probability for each event, we will divide the wanted outcome by the total number of possible outcomes.

Question 1:

Aswer:
(4)/(20)

Explanation:

Landing on a vowel:

(A & E)/(A, B, C, D, E) = 2/5

Landing on an even number:

(2 & 4)/(1, 2, 3, 4) = 2/4

Landing on a vowel and an even number:

2/5 * 2/4 = 4/20

Question 2:

Answer:
(1)/(20)

Explanation:

Landing on C:

(C)/(A, B, C, D, E) = 1/5

Landing on 4:

(4)/(1, 2, 3, 4) = 1/4

Landing on C and 4:

1/5 * 1/4 = 1/20

User Sdaz MacSkibbons
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3.9k points