Final answer:
A 1.00 liter solution contains 0.51 M hydrocyanic acid and 0.38 M sodium cyanide. Adding 40.0 mL of water to this system will result in the number of moles of HNO2 decreasing, the equilibrium concentration of H3O+ increasing, the pH decreasing, and the ratio of [HNO2] / [NO2-] increasing.
Step-by-step explanation:
A. The number of moles of HNO2 will decrease.
B. The number of moles of NO2- will remain the same.
C. The equilibrium concentration of H3O+ will increase.
D. The pH will decrease.
E. The ratio of [HNO2] / [NO2-] will increase.