Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is spun at 440.9 rad/s 440.9 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds 0.569 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

-775 rad/s^2

Step-by-step explanation:

Knowing the initial and final angular speed is
`\omega_0 = 440.9 rad/s` and
`\omega = 0 rad/s`, respectively. We can use the following formula for equation of motion to calculate the average angular acceleration in t = 0.569 seconds

`\Delta \omega = \alpha t`

`\omega - \omega_0 = \alpha t`

`0 - 440.9 = \alpha 0.569`

`\alpha = (-440.9)/(0.569) = -775 rad/s^2`