Question

A shell of mass m and speed v explodes into two identical fragments. If the shell was moving horizontally (the positive x direction) with respect to Earth, and one of the fragments is subsequently moving vertically with speed v, find the velocity ' of the other fragment immediately following the explosion. (Use the following as necessary: v.)

Answer 1

The velocity of the other fragment immediately following the explosion is v .

Step-by-step explanation:

Given :

Mass of original shell , m .

Velocity of shell , + v .

Now , the particle explodes into two half parts , i.e
`(m)/(2)` .

Since , no eternal force is applied in the particle .

Therefore , its momentum will be conserved .

So , Final momentum = Initial momentum

`mv=(mv)/(2)+(mu)/(2)\\\\u=v`

The velocity of the other fragment immediately following the explosion is v .