Question

The amount of cola in a soda machine decreases by a rate of 5% each hour. The amount of

cola in the machine was originally 75 gallons. Write a function that models the amount of cola,
S (in gallons), after h hours.

Answer 1

y=[75(100-5)/100]^h

Explanation:

after 1 hour 75-5/100 *75=75 (100-5)/100

after 2 hour 75(100-5)/100 *(100-5)/100=75(100-5)^2/100^2

=[75(100-5)/100]^2

after h hours =[75(100-5)/100]^h