Question

What is the area of the regular pentagon below?

2.4 yd
3.5 yd
O
O
A. 42.0 yd
B . 30.6 yd2
OC. 8.4 yd

Answer 1

21yd^2

Explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)