Answer:
the tension in the string an instant before it broke = 34 N
Step-by-step explanation:
Given that :
mass of the ball m = 300 g = 0.300 kg
length of the string r = 70 cm = 0.7 m
At highest point, law of conservation of energy can be expressed as :
![(1)/(2) mv^2 = mgh\\\\v = √(2gh)\\\\v = √(2*(9.8 \ m/s^2)*(6.00 \ m - 2.00 \ m))\\\\](https://img.qammunity.org/2021/formulas/physics/college/ed7bid5ywugukm8pby8vh8n7aak9w3pn17.png)
![v = 8.854 \ m/s](https://img.qammunity.org/2021/formulas/physics/college/cmocl5ruegux17t3hckkzq3zrl94eqygxf.png)
The tension in the string is:
![T = (mv^2)/(r)\\\\T = ((0.300 \ kg)*(8.854 \ m/s^2))/(0.70 \ m)\\\\T = 33.59 N\\\\T = 34 \ N](https://img.qammunity.org/2021/formulas/physics/college/j34cbfo2rrkccv2dv0zyouyty77sh3oqic.png)
Thus, the tension in the string an instant before it broke = 34 N