2.2k views
4 votes
5. How many different

codes can a combination
lock have if there are three
numbers on the lock and
each number can be from
0-9?

2 Answers

1 vote

Answer:

Correct answer: Vr = 10³ = 1,000 or V = 720

Explanation:

Given:

Input set of numbers S = {0, 1, 2, ....9} ⇒ x = 10

A string that changes n = 3

I guess the numbers can be repeated as 1,1,1 or 2,3,2....

then these are variations with repetition and the formula is:

Vr (x n) = xⁿ

Vr (10 3) = 10³ = 1,000

if the numbers cannot be repeated then these are variations without repeating and the formula is :

V = (x n) = x (x -1) (x -2) ..... (x - n +1)

(10 - 3 + 1) = 8

V = (10 3) = 10 ·9 · 8 = 720

God is with you!!!

User Bryanjez
by
6.2k points
3 votes

Answer: A three digit combination with a selection of 1 - 9 (Nine numbers) would have 729 combinations,

User Joe Komputer
by
5.8k points