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A gas that has a volume of 27 liters, a temperature of 53 0C, and an unknown pressure has its volume increased to 35 liters and its temperature decreased to 32 0C. If I measure the pressure after the change
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A gas that has a volume of 27 liters, a temperature of 53 0C, and an unknown pressure has its volume increased to 35 liters and its temperature decreased to 32 0C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?

User John Kaster
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Answer:4.29atm

Explanation:P1V1/T1 = P2V2/T2

P1 = P2V2T1/V1T2

P1 = 2*35*53/27*32

P1 = 4.29 atm

User Jacob Pavlock
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