Question

Given the following reaction:

Zn + CuCl2 —> ZnCl2 + Cu

How many moles of ZnCl2 will be produced from 23.0g of Zn, assuming CuCl2 is available in excess?

Answer 1

The answer to your question is 0.35 moles of ZnCl₂

Step-by-step explanation:

Data

moles of ZnCl₂ = ?

mass of Zn = 23 g

mass of CuCl₂ = excess

Balanced chemical reaction

Zn + CuCl₂ ⇒ ZnCl₂ + Cu

Process

1.- Convert the mass of Zn to moles

-Look for the atomic mass of Zn

Atomic mass = 65.4 g

-Convert the grams to moles

65.4 g -------------- 1 mol

23 g ---------------- x

x = (23 x 1)/65.4

x = 23 / 65.4

x = 0.35 moles of Zn

2.- Calculate the moles of ZnCl₂ using proportions and cross multiplication, and the coefficients of the balanced chemical reaction.

1 mol of Zn ---------------- 1 mol of ZnCl₂

0.35 moles of Zn -------- x

x = (0.35 x 1) / 1

x = 0.35 moles of ZnCl₂