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Solve the system of equations algebraically

Solve the system of equations algebraically-example-1

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Answer:

y = x^2 + 8x + 16

y = x + 6

x^2 + 8x + 16 = x + 6

x^2 + 7x + 10= 0

(x + 5)(x+2) = 0

x = -5

x = -2

y = (-5)^2 + 8(-5) + 16

y = 25 - 40 + 16

y = 41 - 40

y = 1

y = -5 + 6= 1

y= (-2)^2 + 8(-2) + 16

y = 4 - 16 + 16 = 4 + 0 = 4

y = -2 + 6 = 4

Point of intersection: (-2, 4)

Explanation:

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