Question

There are 3 paper clips and 5 erasers in a paper sack if 2 items are drawn at random without replacement what is the probability that onwme will draw a paper clip and then an eraser

Answer 1

`(15)/(56)`

Explanation:

This is a probability event that expresses the likelihood of an event to occur.

Number of paper clips in sack = 3

Number of erasers in sack = 5

Problem: Probability that one will draw a paper clip and then an eraser?

These are two mutually exclusive events.

Total number of paper in sack = 3 + 5 = 8

Pr(drawing paper clip) =
`(3)/(8)`

without replacement suggests that the total number of paper in sack will reduce by 1 to 7;

Pr(drawing eraser) =
`(5)/(7)`

So:

Pr(paper clip and eraser ) =
`(3)/(8) x (5)/(7)` =
`(15)/(56)`