Question

An exhaled air bubble underwater at 290.

kPa has volume 18.9mL. What will be its
volume at the water's surface where the
pressure is 104kPa. (Why must a diver
exhale during ascent?)

Answer 1

The answer for the following problem is mentioned below.

• Therefore the final volume of the gas is 52.7 ml.

Step-by-step explanation:

Given:

Initial pressure (
`P_(1)`) = 290 kPa

Final pressure (
`P_(2)`) = 104 kPa

Initial volume (
`V_(1)`) = 18.9 ml

To find:

Final volume (
`V_(2)`)

We know;

From the ideal gas equation;

P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of gas

n represents the no of the moles

R represents the universal gas constant

T represents the temperature of the gas

So;

P × V = constant

P ∝
`(1)/(V)`

From the above equation;

`(P_(1) )/(P_(2) ) = (V_(2) )/(V_(1) )`

`P_(1)` represents the initial pressure of the gas

`P_(2)` represents the final pressure of the gas

`V_(1)` represents the initial volume of the gas

`V_(2)` represents the final volume of the gas

Substituting the values of the above equation;

`(290)/(104)` =
`(V_(2) )/(18.9)`

`V_(2)` = 52.7 ml

Therefore the final volume of the gas is 52.7 ml.