Question

What is the vertex of the quadratic function f(x)=(x-6)(x+2)

Answer 1

Answer: ( 2, -6 )

Explanation:

rewrite y= (x-6)(x+2) in the form y=ax^2+bx+c

Y=(x-6)(x+2)

(x-6)(x+2): x^2-4x-12

y=x^2-4x-12

the parabola params are :

a=1, b= -4, c=-12

x^v=-(-4)/ 2*1

x^v=2

y^v=-16