102k views
2 votes
A 25.00 g solid sample of Ca(OH)2 was added into 1250 mL of 0.400 M HCl aqueous solution. The temperature of the solution was decreased from 36.6oC to 20.0oC. Assuming Ccal of the reaction is 5.225 kJ/oC, how much heat is involved in the reaction?

User Locorecto
by
4.9k points

1 Answer

5 votes

Answer:

86.735 kJ

Step-by-step explanation:

Simply multiply the change in temperature by the Ccal;

(36.6 - 20.0)×5.225 = 86.735

User Pradhyuman Sinh
by
5.4k points