Question

If 684.6g of sucrose (table sugar) are dissolved in 4 liters of water, what would be the molarity of the solution?

The chemical formula for sucrose is C12H22O11 , and the molar mass is 342.3 g/mol. mol/L

Answer 1

If 684.6g of sucrose (table sugar) are dissolved in 4 liters of water, the molarity of the solution is 0.47 M

Step-by-step explanation:

Data given:

mass of sugar = 684.6 grams

molar mass of sucrose = 342.3 grams/mole

volume of water = 4 litres

molarity = ?

molarity is given by the formula =
`(number of moles)/(volume in litres)` equation 1

number of moles =
`(mass)/(atomic mass)` equation 2

For number of moles of sucrose equation 2 is used

putting values in it

number of moles =
`(648.6)/(342.3)`

1.89 moles of sucrose are given.

to known the molarity values are put in first equation or formula:

molarity =
`(1.89)/(4)`

molarity = 0.47 M

thus the molarity of 648.6 grams of sugar in 4 litres of solution is 0.47 M

Answer 2

Molarity of the sucrose solution is 0.5 M.

Step-by-step explanation:

The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,

Number of moles =
`$(given mass)/(molar mass)`

=
`$(684.6 g )/(342.3 g/mol)`

= 2 moles

Molarity =
`$(moles)/(Volume (L))`

=
`$(2)/(4) \\`

= 0.5 moles / litre (mol/ L) or 0.5 M

So the molarity of the sucrose solution is 0.5 M.