Question

Scott and Isaac went to the school carnival. Scott ride on 5 rides and played 4 games. Isaac rode on 7 rides played 2 games. If Scott payed 19 tickets and Isaac payed 23 tickets, how many tickets did a ride cost?

Answer 1

The cost of the rides are 3 tickets

And 1 ticket per game

The ride and game cost 3 tickets and 1 ticket for each respectively.

Explanation:

Step 1 of 5

Let a be the number of tickets per ride costs. And b be the number of tickets per game costs.Thus from the given, we get the equations. For Scott, 5a+4b=19 For Isaac, 7a​+2b=23

Step 2 of 5

Multiplying the equation 2 by 2, we get ​5a+4b=19→1 14a+4b=46→2​

Step 3 of 5

By subtracting both the equations, we get

(−)​5a+4b=1914a+4b=46​

_____________

−9a =−27

​a=−27−9⇒a=3​

Step 4 of 5

Substituting the above value in the equation 1, we get​5(3)+4b=1915+4b=194b=19−154b=4b=44⇒b=1​

Step 5 of 5

The solution is (3,1).The cost of the rides is 3 tickets per ride.The cost of the games is 1 ticket per game.

sorry its really confusing this how I was taught tho.